Answer
$v=3.35m/s$
Work Step by Step
$E= K+U(x)$
$K=E-U(x)$
The total energy ($E$) is equal to $-5.75J$ as calculated in part (c)
Determine $U(x)$ at $ x=7m$ from the graph:
$U(7)= -17J$
$K=E-U$
$\frac{1}{2}mv^2=E-U$
$v^2=\frac{2(E-U)}{m}$
$v=\sqrt {\frac{2(E-U)}{m}}$
$v=\sqrt {\frac{2(-5.75J-(-17J))}{2}}$
$v=\sqrt {\frac{2(-5.75J+17J)}{2}}$
$v=\sqrt {\frac{2(11.25J)}{2}}$
$v=\sqrt {\frac{22.5J}{2}}$
$v=\sqrt {11.25}$
$v=3.35m/s$
