Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 209: 78a

Answer

$K = 216J$

Work Step by Step

$K = \frac{1}{2}mv^2$ $K = \frac{1}{2}\times 300kg \times (1.2m/s)^2$ $K = 216J$
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