Answer
K = 1.00 J
Work Step by Step
From Problem 81e, we got that at x = 11.0 m, K = 2.00 J. According to the graph, to get from x = 11.0 m to x = 12.0 m, the particle will be acted on by a force $F_{4}$ = – 1.00 N, for a displacement d = 1.00 m. Therefore, the force will do a work W = $F_{4}$d = (–1.00 N)(1.00 m) = –1.0 J, which represents the change in kinetic energy. Since originally K = 2.00 J, at x = 12.0 m we’ll have K = 2.00 J + (–1.00 J) = 1.0 J.
