Answer
$1$
Work Step by Step
$log_23\cdot log_34\cdot\cdot\cdot\cdot\cdot\cdot log_n(n+1)\cdot log_{n+1}(2)=\frac{ln3}{ln2}\times\frac{ln4}{ln3}......\times\frac{ln(n+1)}{ln(n)}\times\frac{ln(2)}{ln(n+1)}=\frac{ln2}{ln2}=1$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 4 - Exponential and Logarithmic Functions - Section 4.5 Properties of Logarithms - 4.5 Assess Your Understanding - Page 332: 99
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