Answer
$ log_2(\frac{(x+1)^2}{(x+3)(x-1)})$
Work Step by Step
$2log_2(x+1)-log_2(x+3)-log_2(x-1)=log_2(x+1)^2-log_2(x+3)-log_2(x-1)=log_2(\frac{(x+1)^2}{(x+3)(x-1)})$
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