Answer
$ log_5(\frac{(3x+1)^3}{x(2x-1)^2})$
Work Step by Step
$3log_5(3x+1)-2log_5(2x-1)-log_5(x)=log_5(3x+1)^3-log_5(2x-1)^2-log_5(x)=log_5(\frac{(3x+1)^3}{x(2x-1)^2})$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 4 - Exponential and Logarithmic Functions - Section 4.5 Properties of Logarithms - 4.5 Assess Your Understanding - Page 332: 70
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