Answer
$-3.880$
Work Step by Step
Change of Base Formula: $\hspace{20pt} \log_ a M = \dfrac{\log_b M}{\log_b a}$
$\log_{1/3} 71 = \dfrac{\log_{10} 71}{\log_{10} \dfrac{1}{3}}$
Where: $a=\dfrac{1}{3} \hspace{10pt} M = 71 \hspace{10pt} b = 10$
$ \dfrac{\log_{10} 71}{\log_{10} \dfrac{1}{3}} \approx \boxed{-3.880}$