Answer
See below.
Work Step by Step
Given $f(x)=log_a(x)$, we have $-f(x)=-log_a(x)=-\frac{ln(x)}{ln(a)}=\frac{ln(x)}{ln(a)^{-1}}=\frac{ln(x)}{ln(1/a)}=log_{1/a}(x)$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 4 - Exponential and Logarithmic Functions - Section 4.5 Properties of Logarithms - 4.5 Assess Your Understanding - Page 332: 105
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