Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 533: 97

Answer

$ 30^{\circ}$ and $150^{\circ}$

Work Step by Step

The value of $\sin \theta$ is positive, so $\theta$ may lie in either quadrant I or II. We know that $\sin 30^{\circ}=\frac{1}{2}$. $30^{\circ}$ is in the first quadrant. $\theta$ in the second quadrant can be found using the identity $\sin x=\sin (180^{\circ}-x)$ $\implies \sin 30^{\circ}= \sin (180^{\circ}-30^{\circ})=\sin 150^{\circ}$ The values of $\theta$ are $ 30^{\circ}$ and $150^{\circ}$.
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