Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 533: 65

Answer

$ \frac{\sqrt 3}{2}$, $ \frac{\sqrt 3}{3}$, and $ \frac{2\sqrt 3}{3}$.

Work Step by Step

Given $\theta=60^\circ$, we have $sin\theta = \frac{\sqrt 3}{2}$, $cot\theta = \frac{1}{tan\theta}=\frac{\sqrt 3}{3}$, and $csc\theta=\frac{1}{sin\theta}=\frac{2\sqrt 3}{3}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.