Answer
-1
Work Step by Step
As the period of tangent function is $180^{\circ}$,
$\tan(3015^{\circ})=\tan(3015^{\circ}-(180^{\circ}\times17))=\tan (-45^{\circ})=-\tan 45^{\circ}=-1$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 533: 95
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