Answer
$\frac{\sqrt {3}}{2}$
Work Step by Step
As the period of sine function is $360^{\circ}$,
$\sin1500^{\circ}=\sin(1500^{\circ}-(360^{\circ}\times4))$
$=\sin 60^{\circ}=\frac{\sqrt {3}}{2}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 533: 90
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