Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 533: 85

Answer

$\frac{1}{2}$, $-\frac{\sqrt 3}{2}$, $-\frac{\sqrt 3}{3}$, $-\sqrt 3$, $-\frac{2\sqrt 3}{3}$, and $2$.

Work Step by Step

Given $\theta=-1290^\circ=-3\times360^\circ-210^\circ$ (quadrant II, reference angle $30^\circ$), we have $sin\theta =sin30^\circ=\frac{1}{2}$, $cos\theta =-cos30^\circ=-\frac{\sqrt 3}{2}$, $tan\theta =-tan30^\circ=-\frac{\sqrt 3}{3}$, $cot\theta = \frac{1}{tan\theta}=-\sqrt 3$, $sec\theta = \frac{1}{cos\theta}=-\frac{2\sqrt 3}{3}$, and $csc\theta = \frac{1}{sin\theta}=2$.
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