Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 533: 109

Answer

0.625243

Work Step by Step

Converting $38^{\circ}48'$ to decimal degrees, we get $38^{\circ}42'=38^{\circ}+\frac{42}{60}^{\circ}=38^{\circ}+0.7^{\circ}=38.7^{\circ}$ $\sin 38^{\circ}42'=\sin 38.7^{\circ}\approx0.625243$
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