Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 533: 70

Answer

$\sqrt 3$ and $ \frac{\sqrt 3}{3}$

Work Step by Step

Given $\theta=240^\circ$ (quadrant III), we have $tan\theta =tan60^\circ=\sqrt 3$ and $cot\theta = \frac{1}{tan\theta}=\frac{\sqrt 3}{3}$
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