Answer
$-\frac{\sqrt 3}{2}$, $\frac{1}{2}$, $-\sqrt 3$, $-\frac{\sqrt 3}{3}$, $2$, and $-\frac{2\sqrt 3}{3}$.
Work Step by Step
Given $\theta=-1860^\circ=-5\times360^\circ-60^\circ$ (quadrant IV, reference angle $60^\circ$), we have $sin\theta =-sin60^\circ=-\frac{\sqrt 3}{2}$, $cos\theta =cos60^\circ=\frac{1}{2}$, $tan\theta =-tan60^\circ=-\sqrt 3$, $cot\theta = \frac{1}{tan\theta}=-\frac{\sqrt 3}{3}$, $sec\theta = \frac{1}{cos\theta}=2$, and $csc\theta = \frac{1}{sin\theta}=-\frac{2\sqrt 3}{3}$.
