Answer
$-\frac{\sqrt 3}{2}$ and $ -\frac{2\sqrt 3}{3}$
Work Step by Step
Given $\theta=210^\circ$ (quadrant III), we have $cos\theta =-cos30^\circ=-\frac{\sqrt 3}{2}$ and $sec\theta = \frac{1}{cos\theta}=-\frac{2\sqrt 3}{3}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 533: 69
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