Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 533: 110

Answer

0.750111

Work Step by Step

Converting $41^{\circ}24'$ to decimal degrees, we get $41^{\circ}24'=41^{\circ}+\frac{24}{60}^{\circ}=41^{\circ}+0.4^{\circ}=41.4^{\circ}$ $\cos 41^{\circ}24'=\cos 41.4^{\circ}\approx0.750111$
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