Answer
$\dfrac{2}{3}$
Work Step by Step
Convert each mixed number to an improper fraction to obtain:
$=\left(\dfrac{4\cdot 1 + 3}{4}\right)\div\left(\dfrac{8\cdot 2 + 5}{8}\right)
\\=\dfrac{7}{4}\div\dfrac{21}{8}$
Use the rule $\dfrac{a}{b} \div \dfrac{c}{d} =\dfrac{a}{b} \cdot \dfrac{d}{c}$ to obtain:
$=\dfrac{7}{4} \cdot \dfrac{8}{21}$
Cancel common factors to obtain:
$\require{cancel}
\\=\dfrac{\cancel{7}}{\cancel{4}} \cdot \dfrac{\cancel{8}2}{\cancel{21}3}
\\=\dfrac{1}{1} \cdot \dfrac{2}{3}$
Multiply the numerators together and the denominators together to obtain:
$=\dfrac{1(2)}{1(3)}
\\=\dfrac{2}{3}$
