Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.3 The Rational Numbers - Exercise Set 5.3 - Page 285: 61

Answer

$\dfrac{3}{2}$

Work Step by Step

Cancel the common factors, 2 and 3, to find: $\require{cancel} (-\frac{\cancel{2}}{\cancel{3}})(-\frac{\cancel{9}3}{\cancel{4}2})$ Multiply the numerators together and the denominators together to obtain: $=\dfrac{-1(3)}{-1(2)} \\=\dfrac{3}{2}$
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