Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.3 The Rational Numbers - Exercise Set 5.3 - Page 285: 63

Answer

$6$

Work Step by Step

Convert each mixed number to an improper fraction: $=(\frac{4(3)+3}{4})(\frac{5(1)+3}{5}) \\=(\frac{15}{4})(\frac{8}{5})$ Cancel the common factors: $\require{cancel} =(\frac{\cancel{15}3}{\cancel{4}})(\frac{\cancel{8}2}{\cancel{5}})$ Multiply the numerators together and the denominators together: $=\dfrac{3(2)}{1(1)} \\=\dfrac{6}{1} \\=6$
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