Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.3 The Rational Numbers - Exercise Set 5.3 - Page 285: 64

Answer

$\dfrac{7}{2}$

Work Step by Step

Convert each mixed number to an improper fraction to obtain: $=\left(\dfrac{5(2)+4}{5}\right)\left(\dfrac{4(1)+1}{4}\right) \\=\dfrac{14}{5} \cdot \dfrac{5}{4}$ Cancel common factors to obtain: $\require{cancel} \\=\dfrac{\cancel{14}7}{\cancel{5}} \cdot \dfrac{\cancel{5}}{\cancel{4}2} \\=\dfrac{7}{1} \cdot \dfrac{1}{2}$ Multiply the numerators and multiply the denominators to obtain" $=\dfrac{7(1)}{1(2)} \\=\dfrac{7}{2}$
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