Answer
$\frac{1}{2}sin 2x+C$
Work Step by Step
Let I= $\int cos 2xdx$
Plug in: 2x=u
$⇒dx= \frac{du}{2}$
Then: $I=\int cos u \frac{du}{2}$
$= \frac{1}{2}\int cos u du$
$= \frac{1}{2}\times sin u +C$
$= \frac{1}{2}sin 2x +C$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 8 - Section 8.2 - Trigonometric Integrals - Exercises - Page 434: 1
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