Answer
$$\int e^x\sec^2(e^x-7)dx=\tan(e^x-7)+C$$
Work Step by Step
$$A=\int e^x\sec^2(e^x-7)dx$$
We set $a=e^x-7$, which means $$da=e^xdx$$
Therefore, $$A=\int \sec^2ada$$ $$A=\tan a+C$$ $$A=\tan(e^x-7)+C$$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Practice Exercises - Page 343: 51
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