Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 8: Techniques of Integration - Section 8.3 - Trigonometric Integrals - Exercises 8.3 - Page 463: 66

Answer

$$-\ln |\csc 2 x+\cot 2 x|+C $$

Work Step by Step

We integrate as follows: \begin{align*} \int \frac{\cot x}{\cos ^{2} x} d x&=\int \frac{\cos x}{\sin x} \cdot \frac{1}{\cos ^{2} x} d x\\ &=\int \frac{2}{2 \sin x \cos x} d x\\ &=\int \frac{2}{\sin 2 x} d x\\ &=\int 2\csc 2 x d x\\ &=-\ln |\csc 2 x+\cot 2 x|+C \end{align*}
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