Answer
$$-\frac{2}{5} \cos ^{5} \theta+C $$
Work Step by Step
We integrate as follows:
\begin{align*}
\int \cos ^{3} \theta \sin 2 \theta d \theta&=\int \cos ^{3} \theta(2 \sin \theta \cos \theta) d \theta\\
&=2 \int \cos ^{4} \theta \sin \theta d \theta\\
&=-\frac{2}{5} \cos ^{5} \theta+C
\end{align*}