Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Section 12.2 - Vectors - Exercises 12.2 - Page 704: 9

Answer

$\lt 1,-4 \gt$

Work Step by Step

Suppose two vectors $A$ and $B$ . and, a vector $p$ can be found as: $p=B-A=\lt 2,-1 \gt -\lt 1,3 \gt =\lt 2-1,-1-3 \gt$ or, $=\lt 1,-4 \gt$
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