Answer
$\lt \dfrac{-1}{2},\dfrac{-\sqrt 3}{2} \gt$
Work Step by Step
Since, we have $v=\lt |v| \cos \theta, |v| \sin \theta \gt$ to compute the components of vector $v$
Given: $|v|=1$ and $\theta=\dfrac{2\pi}{3}$
Thus,
$v=\lt (1) \cos (\dfrac{2\pi}{3}), (1) \cos (\dfrac{2\pi}{3}) \gt$
or, $v=\lt \dfrac{-1}{2},\dfrac{-\sqrt 3}{2} \gt$
