Answer
$\lt 1,3\gt$ and $\sqrt {10}$
Work Step by Step
The magnitude of a vector is:$|n|=\sqrt{n_1^2+n_2^2}$
Since, $u=\lt 3,-2 \gt$ and $v=\lt -2,5 \gt $ Thus,
$u+v=\lt 3,-2 \gt+\lt -2,5 \gt =\lt 1,3\gt$
and $|\lt 1,3\gt|=\sqrt{1^2+(3)^2}=\sqrt{1+9}=\sqrt {10}$
Therefore, answers are: $\lt 1,3\gt$ and $\sqrt {10}$
