Answer
$\lt -16,29\gt$ and $\sqrt {1097}$
Work Step by Step
The magnitude of a vector is:$|n|=\sqrt{n_1^2+n_2^2}$
Here, $u=\lt 3,-2 \gt; v= \lt -2,5 \gt$
Now, $-2u +5v=-2\lt 3,-2 \gt +5 \lt -2,5 \gt =\lt -16,29 \gt$
and $|\lt -16,29\gt|=\sqrt{(-16)^2+(29)^2}=\sqrt {1097}$
Hence, we have $\lt -16,29\gt$ and $\sqrt {1097}$
