Answer
$\lt \dfrac{-1}{\sqrt 2},\dfrac{-1}{\sqrt 2} \gt$
Work Step by Step
Since, we have $v=\lt |v| \cos \theta, |v| \sin \theta \gt$ to compute the components of a vector $v$
Given: $|v|=1$ and $\theta=\dfrac{-3\pi}{4}$
Thus,
$v=\lt 1 \cos (\dfrac{-3\pi}{4}), 1 \cos (\dfrac{-3\pi}{4}) \gt$
or, $v=\lt \dfrac{-1}{\sqrt 2},\dfrac{-1}{\sqrt 2} \gt$
