Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Section 12.2 - Vectors - Exercises 12.2 - Page 704: 22

Answer

$5i+3j-k$

Work Step by Step

Given: $u=\lt -1,0,2 \gt$ and $v=\lt 1,1,1 \gt $ Now, $-2u+3v=-2\lt -1,0,2 \gt +3\lt 1,1,1 \gt $ or, $=\lt 2,0,-4 \gt +\lt 3,3,3 \gt$ or, $=\lt 5,3,-1 \gt$ In vector form, we have $5i+3j-k$
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