Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Section 12.2 - Vectors - Exercises 12.2 - Page 704: 15

Answer

$\lt \dfrac{-\sqrt 3}{2},\dfrac{-1}{2} \gt$

Work Step by Step

The unit vector will make an angle with positive x-axis be: $120^{\circ} + 90^{\circ}=210^{\circ}$ when the vector $\lt 0,1 \gt $ is making an angle with counterclockwise positive x-axis. Hence, we have $\lt \cos (210^{\circ}), \sin (210^{\circ}) \gt=\lt \dfrac{-\sqrt 3}{2},\dfrac{-1}{2} \gt$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.