Answer
$\lt 12,-19\gt$ and $\sqrt {505}$
Work Step by Step
The magnitude of a vector is:$|n|=\sqrt{n_1^2+n_2^2}$
Now, $2u -2v=2\lt 3,-2 \gt -2\lt -2,5 \gt =\lt 12,-19\gt$
and $|\lt 12,-19\gt|=\sqrt{(12)^2+(-19)^2}=\sqrt {505}$
Hence, we have $\lt 12,-19\gt$ and $\sqrt {505}$
