Answer
$$dy = \left( {9{x^2} - 4} \right)dx$$
Work Step by Step
$$\eqalign{
& f\left( x \right) = 3{x^3} - 4x \cr
& {\text{Differentiate }} \cr
& f'\left( x \right) = \frac{d}{{dx}}\left[ {3{x^3} - 4x} \right] \cr
& f'\left( x \right) = 9{x^2} - 4 \cr
& {\text{Write in the form }}dy = f'\left( x \right)dx \cr
& dy = \left( {9{x^2} - 4} \right)dx \cr} $$