Answer
\[dy = 2dx\]
Work Step by Step
$$\eqalign{
& f\left( x \right) = 2x + 1 \cr
& {\text{Differentiate}} \cr
& f'\left( x \right) = \frac{d}{{dx}}\left[ {2x + 1} \right] \cr
& f'\left( x \right) = 2 \cr
& {\text{Write in the form }}dy = f'\left( x \right)dx \cr
& dy = 2dx \cr} $$