Answer
$$dy = - \frac{3}{{{x^4}}}dx$$
Work Step by Step
$$\eqalign{
& f\left( x \right) = \frac{1}{{{x^3}}} \cr
& f\left( x \right) = {x^{ - 3}} \cr
& {\text{Differentiate}} \cr
& f'\left( x \right) = \frac{d}{{dx}}\left[ {{x^{ - 3}}} \right] \cr
& f'\left( x \right) = - 3{x^{ - 4}} \cr
& or \cr
& f'\left( x \right) = - \frac{3}{{{x^4}}} \cr
& {\text{Write in the form }}dy = f'\left( x \right)dx \cr
& dy = - \frac{3}{{{x^4}}}dx \cr} $$