Answer
$\frac{d}{dx}\log_3(x+8) = \frac{1}{(x+8)ln(3)}$
Work Step by Step
$\frac{d}{dx}\log_b(x) = \frac{1}{x\ln(b)}$
$\frac{d}{dx}\log_3(x+8) = \frac{1}{(x+8)\ln(3)}$
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