Answer
$-15(\cos {3}x)\times(\csc^{6}3x)$
Work Step by Step
$\dfrac {d}{dx}\left( csc^53x\right) =\dfrac {d}{dx}\left( \sin {3}x\right) ^{-5}=-5\times \left( \sin {3}x\right) ^{-6}\times \left( \cos 3x\right) \times 3=-15(\cos {3}x)\times(csc^{6}3x)$
