Answer
$1$
Work Step by Step
We are given that $G=(2u+v, 5u+3v)$
We need to compute $Jac(G)$.
$Jac(G)=\begin{vmatrix} \dfrac{\partial x}{\partial u} & \dfrac{\partial x}{\partial v} \\ \dfrac{\partial y}{\partial u} & \dfrac{\partial y}{\partial v} \end{vmatrix}$
or, $=\begin{vmatrix} 2 & 1 \\ 5 & 3 \end{vmatrix}$
or, $=(2)(3) -(5)(1)$
Thus, we get: $Jac(G)=1$
