Answer
See the proof below.
Work Step by Step
We have
$$\frac{d}{dt} (a\times r)=\frac{da}{dt} \times r+a\times \frac{dr}{dt}=a\times \frac{dr}{dt}$$
since $a$ is constant, that is, $\frac{da}{dt} =0$.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 14 - Calculus of Vector-Valued Functions - 14.2 Calculus of Vector-Valued Functions - Exercises - Page 720: 38
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
