Answer
$$ i+4k.$$
Work Step by Step
$$
\lim _{t \rightarrow 0} e^{ 2t} i+\ln( t+1)j+ 4 k=
\lim _{t \rightarrow 0} e^{ 2t} i+\lim _{t \rightarrow 0} \ln( t+1)j+\lim _{t \rightarrow 0} 4 k\\=i+0j+4k=i+4k.
$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 14 - Calculus of Vector-Valued Functions - 14.2 Calculus of Vector-Valued Functions - Exercises - Page 720: 3
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