Answer
$$ r'(t)=\langle 1,2t,3t^2 \rangle,$$
$$ r''(t)=\langle 0,2,6t \rangle .$$
Work Step by Step
Since $ r(t)=\langle t,t^2,t^3 \rangle $, then the derivative $ r'(t)$ is given by
$$ r'(t)=\langle 1,2t,3t^2 \rangle,$$
and hence the second derivative $ r''(t)$ is given by
$$ r''(t)=\langle 0,2,6t \rangle.$$