Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - Chapter Review Exercises - Page 702: 46

Answer

An equation of the plane is $2x + y - 4z = - 21$

Work Step by Step

By Theorem 1 of Section 13.5, the equation of a plane through ${P_0} = \left( {{x_0},{y_0},{z_0}} \right)$ with normal vector ${\bf{n}} = \left( {a,b,c} \right)$ is given by $ax + by + cz = d$, where $d = a{x_0} + b{y_0} + c{z_0}$. Therefore, the equation of the plane through $\left( {1, - 3,5} \right)$ with normal vector ${\bf{n}} = \left( {2,1, - 4} \right)$ is $2x + y - 4z = d$, where $d = 2\cdot1 + 1\cdot\left( { - 3} \right) - 4\cdot5 = - 21$. Thus, $2x + y - 4z = - 21$.
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