Answer
$⟨-3,-20,-1⟩$
Work Step by Step
We calculate the cross-product as follows:
$\textbf{w}\times\textbf{u}=\begin{vmatrix}\textbf{i}&\textbf{j}&\textbf{k}\\1&0&-3\\6&-1&2\end{vmatrix}$
$=\textbf{i}(0\times2-(-1\times-3))-\textbf{j}(1\times2-6\times-3)+\textbf{k}((1\times-1)-6\times0)$
$=-3\textbf{i}-20\textbf{j}-\textbf{k}$
That is, $\textbf{w}\times\textbf{u}= ⟨-3,-20,-1⟩$
