Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - Chapter Review Exercises - Page 702: 29

Answer

$\frac{5}{3}$

Work Step by Step

Component of $\textbf{v}$ along $\textbf{w}$= $\frac{\textbf{v}\cdot\textbf{w}}{||\textbf{w}||}$ $\textbf{v}\cdot\textbf{w}=(-2\times1)+(\frac{1}{2}\times2)+(3\times2)=5$ $||\textbf{w}||=\sqrt {1^{2}+2^{2}+2^{2}}=3$ Then, the component of $\textbf{v}$ along $\textbf{w}$= $\frac{5}{3}$
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