Answer
$$l = 54.929$$
Work Step by Step
$$y'=3x^\frac{1}{2}$$
$$l = \int_{0}^{9}\sqrt{1+{(3\sqrt{x})}^2}dx$$
$$l = \int_{0}^{9}\sqrt{1+9x}dx$$
$$l = [\frac{2}{27}{(1+9x)}^\frac{3}{2}]_{0}^{9}$$
$$l = 54.929$$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 7 - Applications of Integration - 7.4 Exercises - Page 473: 6
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