Answer
10
Work Step by Step
$$(1,2)\ and\ (7,10),$$
(a)$$ Distance = \sqrt{{(10-2)}^2+{(7-1)}^2}$$
$$\sqrt{64+36}$$
$$\sqrt{100}=10$$
(b) $$y=\frac{8}{6}x$$
$$ y'=\frac{8}{6}$$
$$ Distance= \int_{1}^{7}\sqrt{1+{(y')}^2}dx$$
$$ = \int_{1}^{7}\sqrt{1+{(\frac{8}{6})}^2}dx$$
$$ = 10
$$
