Answer
17
Work Step by Step
$$(0,0)\ and\ (8,15),$$
(a)$$ Distance = \sqrt{{(8-0)}^2+{(15-0)}^2}$$
$$\sqrt{64+225}$$
$$\sqrt{289}=17$$
(b) $$y=\frac{15}{8}x$$
$$ y'=\frac{15}{8}$$
$$ Distance= \int_{0}^{8}\sqrt{1+{(y')}^2}$$
$$ = \int_{0}^{8}\sqrt{1+{(\frac{15}{8})}^2}dx$$
$$ = 17
$$
