Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 3 - Applications of Differentiation - Review Exercises - Page 239: 53

Answer

$8$

Work Step by Step

When $ x\rightarrow\infty$, the term $\displaystyle \frac{1}{x}\rightarrow 0,$ and $(8+\displaystyle \frac{1}{x})\rightarrow 8+0=8,.$ Thus, $\displaystyle \lim_{x\rightarrow\infty}(8+\frac{1}{x})=8$
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