Answer
$8$
Work Step by Step
When $ x\rightarrow\infty$, the term $\displaystyle \frac{1}{x}\rightarrow 0,$
and $(8+\displaystyle \frac{1}{x})\rightarrow 8+0=8,.$
Thus, $\displaystyle \lim_{x\rightarrow\infty}(8+\frac{1}{x})=8$
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